3.2.74 \(\int \frac {(a^2+2 a b x+b^2 x^2)^{5/2}}{x^6} \, dx\) [174]

Optimal. Leaf size=223 \[ -\frac {a^5 \sqrt {a^2+2 a b x+b^2 x^2}}{5 x^5 (a+b x)}-\frac {5 a^4 b \sqrt {a^2+2 a b x+b^2 x^2}}{4 x^4 (a+b x)}-\frac {10 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}{3 x^3 (a+b x)}-\frac {5 a^2 b^3 \sqrt {a^2+2 a b x+b^2 x^2}}{x^2 (a+b x)}-\frac {5 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{x (a+b x)}+\frac {b^5 \sqrt {a^2+2 a b x+b^2 x^2} \log (x)}{a+b x} \]

[Out]

-1/5*a^5*((b*x+a)^2)^(1/2)/x^5/(b*x+a)-5/4*a^4*b*((b*x+a)^2)^(1/2)/x^4/(b*x+a)-10/3*a^3*b^2*((b*x+a)^2)^(1/2)/
x^3/(b*x+a)-5*a^2*b^3*((b*x+a)^2)^(1/2)/x^2/(b*x+a)-5*a*b^4*((b*x+a)^2)^(1/2)/x/(b*x+a)+b^5*ln(x)*((b*x+a)^2)^
(1/2)/(b*x+a)

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Rubi [A]
time = 0.04, antiderivative size = 223, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {660, 45} \begin {gather*} \frac {b^5 \log (x) \sqrt {a^2+2 a b x+b^2 x^2}}{a+b x}-\frac {5 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{x (a+b x)}-\frac {5 a^2 b^3 \sqrt {a^2+2 a b x+b^2 x^2}}{x^2 (a+b x)}-\frac {a^5 \sqrt {a^2+2 a b x+b^2 x^2}}{5 x^5 (a+b x)}-\frac {5 a^4 b \sqrt {a^2+2 a b x+b^2 x^2}}{4 x^4 (a+b x)}-\frac {10 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}{3 x^3 (a+b x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a^2 + 2*a*b*x + b^2*x^2)^(5/2)/x^6,x]

[Out]

-1/5*(a^5*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(x^5*(a + b*x)) - (5*a^4*b*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(4*x^4*(a +
b*x)) - (10*a^3*b^2*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(3*x^3*(a + b*x)) - (5*a^2*b^3*Sqrt[a^2 + 2*a*b*x + b^2*x^
2])/(x^2*(a + b*x)) - (5*a*b^4*Sqrt[a^2 + 2*a*b*x + b^2*x^2])/(x*(a + b*x)) + (b^5*Sqrt[a^2 + 2*a*b*x + b^2*x^
2]*Log[x])/(a + b*x)

Rule 45

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 660

Int[((d_.) + (e_.)*(x_))^(m_)*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[(a + b*x + c*x^2)^Fra
cPart[p]/(c^IntPart[p]*(b/2 + c*x)^(2*FracPart[p])), Int[(d + e*x)^m*(b/2 + c*x)^(2*p), x], x] /; FreeQ[{a, b,
c, d, e, m, p}, x] && EqQ[b^2 - 4*a*c, 0] &&  !IntegerQ[p] && NeQ[2*c*d - b*e, 0]

Rubi steps

\begin {align*} \int \frac {\left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{x^6} \, dx &=\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \frac {\left (a b+b^2 x\right )^5}{x^6} \, dx}{b^4 \left (a b+b^2 x\right )}\\ &=\frac {\sqrt {a^2+2 a b x+b^2 x^2} \int \left (\frac {a^5 b^5}{x^6}+\frac {5 a^4 b^6}{x^5}+\frac {10 a^3 b^7}{x^4}+\frac {10 a^2 b^8}{x^3}+\frac {5 a b^9}{x^2}+\frac {b^{10}}{x}\right ) \, dx}{b^4 \left (a b+b^2 x\right )}\\ &=-\frac {a^5 \sqrt {a^2+2 a b x+b^2 x^2}}{5 x^5 (a+b x)}-\frac {5 a^4 b \sqrt {a^2+2 a b x+b^2 x^2}}{4 x^4 (a+b x)}-\frac {10 a^3 b^2 \sqrt {a^2+2 a b x+b^2 x^2}}{3 x^3 (a+b x)}-\frac {5 a^2 b^3 \sqrt {a^2+2 a b x+b^2 x^2}}{x^2 (a+b x)}-\frac {5 a b^4 \sqrt {a^2+2 a b x+b^2 x^2}}{x (a+b x)}+\frac {b^5 \sqrt {a^2+2 a b x+b^2 x^2} \log (x)}{a+b x}\\ \end {align*}

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Mathematica [A]
time = 0.02, size = 79, normalized size = 0.35 \begin {gather*} -\frac {\sqrt {(a+b x)^2} \left (a \left (12 a^4+75 a^3 b x+200 a^2 b^2 x^2+300 a b^3 x^3+300 b^4 x^4\right )-60 b^5 x^5 \log (x)\right )}{60 x^5 (a+b x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a^2 + 2*a*b*x + b^2*x^2)^(5/2)/x^6,x]

[Out]

-1/60*(Sqrt[(a + b*x)^2]*(a*(12*a^4 + 75*a^3*b*x + 200*a^2*b^2*x^2 + 300*a*b^3*x^3 + 300*b^4*x^4) - 60*b^5*x^5
*Log[x]))/(x^5*(a + b*x))

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Maple [A]
time = 0.48, size = 76, normalized size = 0.34

method	result	size
default	\(\frac {\left (\left (b x +a \right )^{2}\right )^{\frac {5}{2}} \left (60 b^{5} \ln \left (x \right ) x^{5}-300 a \,b^{4} x^{4}-300 a^{2} b^{3} x^{3}-200 a^{3} x^{2} b^{2}-75 a^{4} b x -12 a^{5}\right )}{60 x^{5} \left (b x +a \right )^{5}}\)	\(76\)
risch	\(\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (-5 a \,b^{4} x^{4}-5 a^{2} b^{3} x^{3}-\frac {10}{3} a^{3} x^{2} b^{2}-\frac {5}{4} a^{4} b x -\frac {1}{5} a^{5}\right )}{\left (b x +a \right ) x^{5}}+\frac {b^{5} \ln \left (x \right ) \sqrt {\left (b x +a \right )^{2}}}{b x +a}\)	\(88\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b^2*x^2+2*a*b*x+a^2)^(5/2)/x^6,x,method=_RETURNVERBOSE)

[Out]

1/60*((b*x+a)^2)^(5/2)*(60*b^5*ln(x)*x^5-300*a*b^4*x^4-300*a^2*b^3*x^3-200*a^3*x^2*b^2-75*a^4*b*x-12*a^5)/x^5/
(b*x+a)^5

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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 340 vs. \(2 (151) = 302\).
time = 0.30, size = 340, normalized size = 1.52 \begin {gather*} \left (-1\right )^{2 \, b^{2} x + 2 \, a b} b^{5} \log \left (2 \, b^{2} x + 2 \, a b\right ) - \left (-1\right )^{2 \, a b x + 2 \, a^{2}} b^{5} \log \left (\frac {2 \, a b x}{{\left | x \right |}} + \frac {2 \, a^{2}}{{\left | x \right |}}\right ) + \frac {\sqrt {b^{2} x^{2} + 2 \, a b x + a^{2}} b^{6} x}{2 \, a^{2}} + \frac {3 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2}} b^{5}}{2 \, a} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} b^{6} x}{4 \, a^{4}} + \frac {7 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} b^{5}}{12 \, a^{3}} - \frac {2 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} b^{5}}{15 \, a^{5}} - \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} b^{4}}{3 \, a^{4} x} + \frac {2 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} b^{3}}{15 \, a^{5} x^{2}} - \frac {11 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} b^{2}}{60 \, a^{4} x^{3}} + \frac {3 \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}} b}{20 \, a^{3} x^{4}} - \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {7}{2}}}{5 \, a^{2} x^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2)^(5/2)/x^6,x, algorithm="maxima")

[Out]

(-1)^(2*b^2*x + 2*a*b)*b^5*log(2*b^2*x + 2*a*b) - (-1)^(2*a*b*x + 2*a^2)*b^5*log(2*a*b*x/abs(x) + 2*a^2/abs(x)
) + 1/2*sqrt(b^2*x^2 + 2*a*b*x + a^2)*b^6*x/a^2 + 3/2*sqrt(b^2*x^2 + 2*a*b*x + a^2)*b^5/a + 1/4*(b^2*x^2 + 2*a
*b*x + a^2)^(3/2)*b^6*x/a^4 + 7/12*(b^2*x^2 + 2*a*b*x + a^2)^(3/2)*b^5/a^3 - 2/15*(b^2*x^2 + 2*a*b*x + a^2)^(5
/2)*b^5/a^5 - 1/3*(b^2*x^2 + 2*a*b*x + a^2)^(5/2)*b^4/(a^4*x) + 2/15*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*b^3/(a^5*
x^2) - 11/60*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*b^2/(a^4*x^3) + 3/20*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)*b/(a^3*x^4)
- 1/5*(b^2*x^2 + 2*a*b*x + a^2)^(7/2)/(a^2*x^5)

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Fricas [A]
time = 1.70, size = 59, normalized size = 0.26 \begin {gather*} \frac {60 \, b^{5} x^{5} \log \left (x\right ) - 300 \, a b^{4} x^{4} - 300 \, a^{2} b^{3} x^{3} - 200 \, a^{3} b^{2} x^{2} - 75 \, a^{4} b x - 12 \, a^{5}}{60 \, x^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2)^(5/2)/x^6,x, algorithm="fricas")

[Out]

1/60*(60*b^5*x^5*log(x) - 300*a*b^4*x^4 - 300*a^2*b^3*x^3 - 200*a^3*b^2*x^2 - 75*a^4*b*x - 12*a^5)/x^5

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (\left (a + b x\right )^{2}\right )^{\frac {5}{2}}}{x^{6}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b**2*x**2+2*a*b*x+a**2)**(5/2)/x**6,x)

[Out]

Integral(((a + b*x)**2)**(5/2)/x**6, x)

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Giac [A]
time = 1.33, size = 93, normalized size = 0.42 \begin {gather*} b^{5} \log \left ({\left | x \right |}\right ) \mathrm {sgn}\left (b x + a\right ) - \frac {300 \, a b^{4} x^{4} \mathrm {sgn}\left (b x + a\right ) + 300 \, a^{2} b^{3} x^{3} \mathrm {sgn}\left (b x + a\right ) + 200 \, a^{3} b^{2} x^{2} \mathrm {sgn}\left (b x + a\right ) + 75 \, a^{4} b x \mathrm {sgn}\left (b x + a\right ) + 12 \, a^{5} \mathrm {sgn}\left (b x + a\right )}{60 \, x^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b^2*x^2+2*a*b*x+a^2)^(5/2)/x^6,x, algorithm="giac")

[Out]

b^5*log(abs(x))*sgn(b*x + a) - 1/60*(300*a*b^4*x^4*sgn(b*x + a) + 300*a^2*b^3*x^3*sgn(b*x + a) + 200*a^3*b^2*x
^2*sgn(b*x + a) + 75*a^4*b*x*sgn(b*x + a) + 12*a^5*sgn(b*x + a))/x^5

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{5/2}}{x^6} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a^2 + b^2*x^2 + 2*a*b*x)^(5/2)/x^6,x)

[Out]

int((a^2 + b^2*x^2 + 2*a*b*x)^(5/2)/x^6, x)

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